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Question: If \(nC_{r - 1} = 36,^{n}C_{r} = 84\) and \(nC_{r + 1} = 126\) then the value of r is...

If nCr1=36,nCr=84nC_{r - 1} = 36,^{n}C_{r} = 84 and nCr+1=126nC_{r + 1} = 126 then the value of r is

A

1

B

2

C

3

D

None of these

Answer

3

Explanation

Solution

Here nCr1nCr=3684\frac{nC_{r - 1}}{nC_{r}} = \frac{36}{84} and nCrnCr+1=84126\frac{nC_{r}}{nC_{r + 1}} = \frac{84}{126}

3n10r=33n - 10r = - 3 and 4n10r=64n - 10r = 6; on solving we get n=9n = 9 and r=3r = 3.