Question
Question: If \(nC_{r - 1} = 36,^{n}C_{r} = 84\) and \(nC_{r + 1} = 126\) then the value of r is...
If nCr−1=36,nCr=84 and nCr+1=126 then the value of r is
A
1
B
2
C
3
D
None of these
Answer
3
Explanation
Solution
Here nCrnCr−1=8436 and nCr+1nCr=12684
3n−10r=−3 and 4n−10r=6; on solving we get n=9 and r=3.