Question
Question: If \(nC_{r - 1} = 36,\mspace{6mu}^{n}C_{r} = 84\) and \(nC_{r + 1} = 126\), then the value of \(r\)...
If nCr−1=36,6munCr=84 and nCr+1=126, then the
value of r is.
A
1
B
2
C
3
D
None of these
Answer
3
Explanation
Solution
Here nCrnCr−1 = 8436 and nCr+1nCr=12684.
⇒ 3n−10r=−3 and 4n−10r=6
On solving, we getn=9,r=3.