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Question

Question: If \(nC_{r - 1} = 36,\mspace{6mu}^{n}C_{r} = 84\) and \(nC_{r + 1} = 126\), then the value of \(r\)...

If nCr1=36,6munCr=84nC_{r - 1} = 36,\mspace{6mu}^{n}C_{r} = 84 and nCr+1=126nC_{r + 1} = 126, then the

value of rr is.

A

1

B

2

C

3

D

None of these

Answer

3

Explanation

Solution

Here nCr1nCr\frac{nC_{r - 1}}{nC_{r}} = 3684\frac{36}{84} and nCrnCr+1=84126\frac{nC_{r}}{nC_{r + 1}} = \frac{84}{126}.

3n10r=33n - 10r = - 3 and 4n10r=64n - 10r = 6

On solving, we getn=9n = 9,r=3r = 3.