Solveeit Logo

Question

Question: If \({n^{th}}\) term of an A.P. is \(2n + 1\), what is the sum of its first three terms?...

If nth{n^{th}} term of an A.P. is 2n+12n + 1, what is the sum of its first three terms?

Explanation

Solution

A.P. is a sequence in which every set of consecutive terms have a common difference. We will first find the first three terms by putting n=1,2n = 1,2 and 3 in the expression of nth{n^{th}} term of the arithmetic sequence, which is 2n+12n + 1. Then we will add those terms to find the sum of the first three terms of the A.P.

Complete step-by-step answer:
We are given that the nth{n^{th}} term of the sequence is 2n+12n + 1
We have to find the sum of the first three terms.
We will begin by finding the first three terms of the given A.P.
For, first term let n=1n = 1, then first term is 2(1)+1=2+1=32\left( 1 \right) + 1 = 2 + 1 = 3
Now we will substitute n=2n = 2 in the given expression to find the second term of A.P.
2(2)+1=52\left( 2 \right) + 1 = 5
Similarly, we will substitute n=3n = 3 in the expression to find its third term.
2(3)+1=72\left( 3 \right) + 1 = 7
Hence, the first three terms of the A.P. is 3,5,7
We will add these terms to find the sum of the first three terms of A.P.
3+5+7=153 + 5 + 7 = 15
Hence, the sum of the first three terms of the A.P is 15.

Note: We can also do this question by finding only first and third term and then apply the formula n2(a1+an)\dfrac{n}{2}\left( {{a_1} + {a_n}} \right), where a1{a_1} is the first term, an{a_n} is the last term and nn is the number of terms. Also, we can find the value of any term using the formula, an=a1+(n1)d{a_n} = {a_1} + \left( {n - 1} \right)d, where dd is the common difference.