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Physics Question on Resistance

If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be

A

KSS+G\frac{KS}{S+G}

B

G+SnKs\frac{G+S}{nKs}

C

nKsG+S\frac{nKs}{G+S}

D

nK(G+S)s\frac{nK(G+S)}{s}

Answer

KSS+G\frac{KS}{S+G}

Explanation

Solution

The correct option is(D): nK(G+S)s\frac{nK(G+S)}{s}

According to the information, current through galvanometer = nK

n represents the actual number of deflections

⇒ss+Gi=nK⇒\frac{s}{s+G}i=nK

⇒i=nK(S+G)s⇒i=\frac{nK(S+G)}{s}