Question
Question: If \(n \neq 3k\) and 1, \(\omega\), \(\omega^{2}\) are the cube roots of unity, then \(\Delta = \lef...
If n=3k and 1, ω, ω2 are the cube roots of unity, then Δ=1ω2nωnωn1ω2nω2nωn1 has the value
A
0
B
ω
C
ω2
D
1
Answer
0
Explanation
Solution
Applying C1→C1+C2+C3, we get
Δ=1+ωn+ω2n1+ωn+ω2n1+ωn+ω2nωn1ω2nω2nωn1 =000ωn1ω2nω2nωn1=0
(∵1+ωn+ω2n=0ifnisnotmultipleof3)