Question

If $N_A$ is Avogadro's number, then the number of oxygen atom in one g-equivalent of oxygen is

• A. $N_A$
• B. $N_A/2$
• C. $N_A/4$
• D. $2 N_A$

Answer 1

Answer: (B)

$N_A/2$

Answer 2

$G.M.M.$ of $O_{2}=32\,g$ E mass $=\frac{\text{At . mass of O}}{\text{valency}}=\frac{16}{2}=8$ $32 \,g$ of oxygen contain oxygen atoms $= 2 \times N_{A}$ $\therefore 8\,g$ of oxygen contains oxygen atom $=\frac{2\times N_{A}}{4}=N_{A}/ 2$