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Question

Mathematics Question on Derivatives

If n1Cr=(k28)nCr+1n-1C_r= (k^2-8)^nC_r+1 Find kk.

A

k[3,22)(22,3)k\in[-3,-2\sqrt2) \cup(2\sqrt2,3)

B

k[4,23(23,4]k\in [-4,-2\sqrt3\cup(2\sqrt3,4]

C

k[23,4]k\in [2\sqrt3,4]

D

k[3,23]k\in[3,2\sqrt3]

Answer

k[3,22)(22,3)k\in[-3,-2\sqrt2) \cup(2\sqrt2,3)

Explanation

Solution

The correct option is (A): k[3,22)(22,3)k\in[-3,-2\sqrt2) \cup(2\sqrt2,3)