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Question

Mathematics Question on Trigonometric Identities

If n=100!, then what is the value of the following?1log2⁡n+1log3⁡n+1log4⁡n+……+1log100⁡n

A

(A) 0

B

(B) 1

C

(C) 2

D

(D) 3

Answer

(B) 1

Explanation

Solution

Explanation:
Given:1log2⁡n+1log3⁡n+1log4⁡n+…..+1log100⁡n=logn⁡2+logn⁡3+logn⁡4+…..+logn⁡100=logn⁡[2×3×4×…×100]=logn⁡100!=log100!⁡100!=1Hence, the correct option is (B).