Question

If momentum [P], area [A] and time [T] are taken as fundamental quantities, then the dimensional formula for the coefficient of viscosity is

• A. [PA–1T0]
• B. [PAT–1]
• C. [PA–1T]
• D. [PA–1T–1]

Answer 1

Answer: (A)

[PA–1T0]

Answer 2

Explanation:

Viscosity = pascal. second
$[P]^x[A]^y[T]^z=M^{1}L^{−1}T^{−1}$
$M^1L+1T−[1]^x[L^2]^y[T^1]^z=M^1L^{−1}T^{−1}$
$M^xL^{+x+2y}\text{ }T^{−x+z}=M^1L^{−1}T^{−1}$
$x+2y=−1$ −x+z=−1$$$ x=1$$y=−1$$z=0$

$\text{The correct option is (A): i.e., Viscosity} = [PA^{–1}T^0]$