Question

If Mohan has 3 tickets of a lottery containing 3 prizes and 9 blanks, then his chance of winning prize are

• A. 34/55
• B. 21/55
• C. 17/55
• D. None of these

Answer 1

Answer: (A)

34/55

Answer 2

Mohan can gets one prize, 2 prizes or 3 prizes and his chance of failure means he get to prize.

Number of total ways =

Favourable number of ways to be failure = ${ } ^ { 9 } \mathrm { C } _ { 3 } = 84$

Hence required probability = 1 - $\frac { 84 } { 220 } = \frac { 34 } { 55 }$