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Question: If \(A = 3 \hat { i } + 4 \hat { j }\) and ![](https://cdn.pureessence.tech/canvas_240.png?top_left_...

If A=3i^+4j^A = 3 \hat { i } + 4 \hat { j } and the vector having the same magnitude as B and parallel to A is

A

5i^+20j^5 \hat { i } + 20 \hat { j }

B

15i^+10j^15 \hat { i } + 10 \hat { j }

C

20i^+15j^20 \hat { i } + 15 \hat { j }

D

15i^+20j^15 \hat { i } + 20 \hat { j }

Answer

15i^+20j^15 \hat { i } + 20 \hat { j }

Explanation

Solution

B=72+(24)2| B | = \sqrt { 7 ^ { 2 } + ( 24 ) ^ { 2 } } =625= \sqrt { 625 } =25= 25

Unit vector in the direction of A will be A^=3i^+4j^5\hat { A } = \frac { 3 \hat { i } + 4 \hat { j } } { 5 }

So required vector ==15i^+20j^= 15 \hat { i } + 20 \hat { j }