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Question: If ![](https://cdn.pureessence.tech/canvas_438.png?top_left_x=1467&top_left_y=0&width=300&height=142...

If are two vectors, which of the following is not correct?

A

A→+B→=B→+A→\overrightarrow { \mathrm { A } } + \overrightarrow { \mathrm { B } } = \overrightarrow { \mathrm { B } } + \overrightarrow { \mathrm { A } }

B

A⃗⋅B⃗=B⃗⋅A⃗\vec { A } \cdot \vec { B } = \vec { B } \cdot \vec { A }

C

A→×B→=B→×A→\overrightarrow { \mathrm { A } } \times \overrightarrow { \mathrm { B } } = \overrightarrow { \mathrm { B } } \times \overrightarrow { \mathrm { A } }

D

Answer

A→×B→=B→×A→\overrightarrow { \mathrm { A } } \times \overrightarrow { \mathrm { B } } = \overrightarrow { \mathrm { B } } \times \overrightarrow { \mathrm { A } }

Explanation

Solution

Vector product of two vectors is not commutative.

i.e., A→×B→≠B→×A→\overrightarrow { \mathrm { A } } \times \overrightarrow { \mathrm { B } } \neq \overrightarrow { \mathrm { B } } \times \overrightarrow { \mathrm { A } }

A→×B→=−B→×A→\overrightarrow { \mathrm { A } } \times \overrightarrow { \mathrm { B } } = - \overrightarrow { \mathrm { B } } \times \overrightarrow { \mathrm { A } }