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Question: If \(( a + i b ) ( c + i d ) ( e + i f ) ( g + i h )\) \(z_{1} = z_{2}\) then \((x + iy)(p + iq) = ...

If (a+ib)(c+id)(e+if)(g+ih)( a + i b ) ( c + i d ) ( e + i f ) ( g + i h ) z1=z2z_{1} = z_{2} then

(x+iy)(p+iq)=(x2+y2)i(x + iy)(p + iq) = (x^{2} + y^{2})i =

A

p=x,q=yp = x,q = y

B

p=x2,q=y2p = x^{2},q = y^{2}

C

x=q,y=px = q,y = p

D

A+iBA + iB

Answer

p=x,q=yp = x,q = y

Explanation

Solution

2xy−y=02xy - y = 0 .....(i)

⇒ y=0y = 0 ......(ii)

Multiplying (i) and (ii), we get

x=12x = \frac{1}{2}