Question
Question: If \(\theta\) is...
If θ is
A
3π
B
2π
C
32π
D
−32π
Answer
3π
Explanation
Solution
θ=sin−1[sin(−600∘)] = sin−1[−sin(360+240)]
⇒ =sin−1[−sin(180∘+60∘)]
⇒ =sin−1[sin(3π)]=3π
If θ is
3π
2π
32π
−32π
3π
θ=sin−1[sin(−600∘)] = sin−1[−sin(360+240)]
⇒ =sin−1[−sin(180∘+60∘)]
⇒ =sin−1[sin(3π)]=3π