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Question: If \(\lambda _ { 2 }\)respectively incident on a metallic surface. If ![](https://cdn.pureessence.te...

If λ2\lambda _ { 2 }respectively incident on a metallic surface. If

A

K1>(K2/3)\mathrm { K } _ { 1 } > \left( \mathrm { K } _ { 2 } / 3 \right)

B

C

K1=3 K2\mathrm { K } _ { 1 } = 3 \mathrm {~K} _ { 2 }

D

K2=3 K1\mathrm { K } _ { 2 } = 3 \mathrm {~K} _ { 1 }

Answer

Explanation

Solution

: According to Einstein’s photoelectric equation

hcλ=ϕ0+KEmax\frac { h c } { \lambda } = \phi _ { 0 } + K E _ { \max }

Where ϕ0\phi _ { 0 }is work function of a metal

Or

Or K1=K223K223ϕ0=K2323ϕ0K _ { 1 } = K _ { 2 } - \frac { 2 } { 3 } K _ { 2 } - \frac { 2 } { 3 } \phi _ { 0 } = \frac { K _ { 2 } } { 3 } - \frac { 2 } { 3 } \phi _ { 0 } or K1<K23K _ { 1 } < \frac { K _ { 2 } } { 3 }