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Question

Question: If matrix \(A = \begin{bmatrix} 3 & 2 & 4 \\ 1 & 2 & - 1 \\ 0 & 1 & 1 \end{bmatrix}\)and \(A^{- 1} =...

If matrix A=[324121011]A = \begin{bmatrix} 3 & 2 & 4 \\ 1 & 2 & - 1 \\ 0 & 1 & 1 \end{bmatrix}and A1=1Kadj(A)A^{- 1} = \frac{1}{K}adj(A), then K is

A

7

B

–7

C

1/7

D

11

Answer

11

Explanation

Solution

We know that A1=adj(A)AA^{- 1} = \frac{adj(A)}{|A|}. We have A1=1Kadj(A)A^{- 1} = \frac{1}{K}adj(A) i.e.

K=AK = |A|

and K=324121011K = \left| \begin{matrix} 3 & 2 & 4 \\ 1 & 2 & - 1 \\ 0 & 1 & 1 \end{matrix} \right| =3(3)2(1)+4(1)=92+4=11= 3(3) - 2(1) + 4(1) = 9 - 2 + 4 = 11