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Question: If \(\mathbf{a} \times \mathbf{b} = \mathbf{b} \times \mathbf{c} \neq 0\) and \(\mathbf{a} + \mathbf...

If a×b=b×c0\mathbf{a} \times \mathbf{b} = \mathbf{b} \times \mathbf{c} \neq 0 and a+c0,\mathbf{a} + \mathbf{c} \neq 0, then

A

(a+c)b(\mathbf{a} + \mathbf{c})\bot\mathbf{b}

B

(a+c)b(\mathbf{a} + \mathbf{c})||\mathbf{b}

C

a+c=b\mathbf{a} + \mathbf{c} = \mathbf{b}

D

None of these

Answer

(a+c)b(\mathbf{a} + \mathbf{c})||\mathbf{b}

Explanation

Solution

a×b=b×c(a+c)×b=0,\mathbf{a} \times \mathbf{b} = \mathbf{b} \times \mathbf{c} \Rightarrow (\mathbf{a} + \mathbf{c}) \times \mathbf{b} = 0, but a+c0\mathbf{a} + \mathbf{c} \neq 0

a+cb.\Rightarrow \mathbf{a} + \mathbf{c}||\mathbf{b}.