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Question: If \(\mathbf{a} \neq \mathbf{0},\mathbf{b} \neq \mathbf{0},\mathbf{c} \neq \mathbf{0}\), then true s...

If a≠0,b≠0,c≠0\mathbf{a} \neq \mathbf{0},\mathbf{b} \neq \mathbf{0},\mathbf{c} \neq \mathbf{0}, then true statement is

A

a×(b+c)=(c+b)×a\mathbf{a} \times (\mathbf{b} + \mathbf{c}) = (\mathbf{c} + \mathbf{b}) \times \mathbf{a}

B

a.(b+c)=−(b+c).a\mathbf{a}.(\mathbf{b} + \mathbf{c}) = - (\mathbf{b} + \mathbf{c}).\mathbf{a}

C

a×(b−c)=(c−b)×a\mathbf{a} \times (\mathbf{b} - \mathbf{c}) = (\mathbf{c} - \mathbf{b}) \times \mathbf{a}

D

a.(b−c)=(c−b).a\mathbf{a}.(\mathbf{b} - \mathbf{c}) = (\mathbf{c} - \mathbf{b}).\mathbf{a}

Answer

a×(b−c)=(c−b)×a\mathbf{a} \times (\mathbf{b} - \mathbf{c}) = (\mathbf{c} - \mathbf{b}) \times \mathbf{a}

Explanation

Solution

It is obvious.