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Question: If mass of proton = 1.008 amu and mass of neutron = 1.009 amu, then the binding energy per nucleon f...

If mass of proton = 1.008 amu and mass of neutron = 1.009 amu, then the binding energy per nucleon for 4Be9 (mass = 9.012 amu.) will be –

A

0.0672 MeV

B

0.672 MeV

C
  1. 724 MeV
D

67.2 MeV

Answer
  1. 724 MeV
Explanation

Solution

Binding energy

= [4 × 1.008 + 5 × 1.009 – 9.012] × 931.5 MeV

= [0.032 + 0.045 – 0.012] × 931.5 MeV

= 0.065 × 931.5 MeV

= 60.55 MeV

= 6.724 MeV