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Question: If mass of proton = 1.008 amu and mass of neutron = 1.009 amu, then the binding energy per nucleon f...

If mass of proton = 1.008 amu and mass of neutron = 1.009 amu, then the binding energy per nucleon for 4Be9 (mass = 9.012 a.m.u.) will be

A

0.0672 MeV

B

0.672 MeV

C

6.724 MeV

D

67.2 MeV

Answer

6.724 MeV

Explanation

Solution

Dm = (4mp + 5mn) – M

DE = Dm × 931 MeV

ΔEA\frac { \Delta \mathrm { E } } { \mathrm { A } }= Δm×931MeV9\frac { \Delta \mathrm { m } \times 931 \mathrm { MeV } } { 9 }