Question
Physics Question on Waves
If man were standing unsymmetrically between parallel cliffs, claps his hands and starts hearing a series of echoes at intervals of 1s. If speed of sound in air is 340ms−1, the distance between two cliffs would be
A
340 m
B
510 m
C
170 m
D
680 m
Answer
510 m
Explanation
Solution
Let x be distance of person from one cliff and y be distance of person from 2nd cliff Let y>x ∴x+x=v×t1=340×1=340 x=170m y+y=V×t2=340×2=680 y=340m Distance between two cliffs =x+y=170+340=510m