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Question

Physics Question on Waves

If man were standing unsymmetrically between parallel cliffs, claps his hands and starts hearing a series of echoes at intervals of 1s1\, s. If speed of sound in air is 340ms1340 \,m\,s^{-1}, the distance between two cliffs would be

A

340 m

B

510 m

C

170 m

D

680 m

Answer

510 m

Explanation

Solution

Let x be distance of person from one cliff and y be distance of person from 2nd2^{nd} cliff Let y>xy \,>\,x x+x=v×t1=340×1=340\therefore x+x = v \times t_{1}=340\times1=340 x=170m x = 170\, m y+y=V×t2=340×2=680y + y = V \times t_2=340 \times 2 =680 y=340m y = 340\, m Distance between two cliffs =x+y=170+340=510m= x + y = 170 + 340 = 510\, m