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Question: If magnitude of a complex number \[z=4-3i\] is tripled and is rotated anti clockwise by an angle of ...

If magnitude of a complex number z=43iz=4-3i is tripled and is rotated anti clockwise by an angle of π\pi , then the resulting complex number would be
1. 12+9i-12+9i
2. 12+9i12+9i
3. 76i7-6i
4. 7+6i7+6i

Explanation

Solution

To solve this question you must first start by taking the magnitude of the given complex number. Let the complex number be z and its magnitude will be z\left| z \right| and the formula to find its magnitude will be a2+b2\sqrt{{{a}^{2}}+{{b}^{2}}} . Now we need to find the complex number which we will obtain after rotating the complex number z. Let the resulting complex number be z1{{z}_{1}} and we can find it by using the formula z1=eiπ{{z}_{1}}={{e}^{-i\pi }}

Complete step by step answer:
Now to start the solution let us assume that
z=43iz=4-3i
Now to find the magnitude of z we can use it by the formula that
z=a2+b2\left| z \right|=\sqrt{{{a}^{2}}+{{b}^{2}}}
Here we know that a is the real part of the complex number and b is the imaginary part of it. Therefore substituting their values inside the formula we get
z=42+32\left| z \right|=\sqrt{{{4}^{2}}+{{3}^{2}}}
Simplifying we get
z=5\left| z \right|=5
Now we also know that the complex number is tripled in size therefore the magnitude of required complex number will be
z1=5×3\left| {{z}_{1}} \right|=5\times 3
z1=15\left| {{z}_{1}} \right|=15
Now that we know the magnitude we know that the complex number is then rotated anticlockwise by π\pi which means that the new complex number vector will be
z1=eiπz=(cosiπsiniπ)z{{z}_{1}}={{e}^{-i\pi }}z=(\cos i\pi -\sin i\pi )z
Therefore simplifying we get
z1=4+3i{{z}_{1}}=-4+3i
Now we know that the new vector is in the direction of the unit vector which is 45+3i5-\dfrac{4}{5}+\dfrac{3i}{5}
Now henceforth our required vector we can say will be since its magnitude is 1515
z1=15(45+3i5){{z}_{1}}=15\left( -\dfrac{4}{5}+\dfrac{3i}{5} \right)
z1=12+9i{z}_{1}=-12+9i

So, the correct answer is “Option 1”.

Note: Argand plane is a plane where we can represent any complex number in the easiest way. Here in this plane the x axis which is the horizontal axis represents all real numbers whereas the y axis which is the vertical axis represents all the imaginary numbers .