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Question: If \(M \cup N = N \cup R\) and \(M \cap N = N \cap R\) then which of the following is necessarily tr...

If MN=NRM \cup N = N \cup R and MN=NRM \cap N = N \cap R then which of the following is necessarily true?
A. M=NM = N
B. N=RN = R
C. M=RM = R
D. M=N=RM = N = R

Explanation

Solution

Here we need to choose the option that suits the given MN=NRM \cup N = N \cup R and MN=NRM \cap N = N \cap R. We need to apply the important property of union and intersection to obtain the desired answer. The union of the two given sets and the intersection of the sets are commutative. Using the commutative property, we can choose the correct option.

Complete step-by-step answer:
We are given MN=NRM \cup N = N \cup R and MN=NRM \cap N = N \cap R
Before getting into the solution, we shall consider an example.
Let A = \left\\{ {1,2,3,5} \right\\} and B = \left\\{ {2,4,5,6,7} \right\\}
Now, we shall calculate the union of the above two sets.
To find the union of the sets, we need to combine all the elements of both sets.
Thus, we have A \cup B = \left\\{ {1,2,3,4,5,6,7} \right\\}
Now, we shall find the commutative of the union of the above two sets (i.e. we need to obtain BCB \cup C )
Hence, we get B \cup C = \left\\{ {1,2,3,4,5,6,7} \right\\}
We can note that AB=BAA \cup B = B \cup A
That is, the commutative property holds for the union of two sets.
Similarly, we shall calculate the intersection of the above two sets.
To find the intersection of the sets, we need to collect the common elements from the sets.
Thus, we have A \cap B = \left\\{ {2,5} \right\\}
Now, we shall find the commutative of the intersection of the above two sets (i.e. we need to obtain BCB \cap C )
Hence, we get B \cap C = \left\\{ {2,5} \right\\}
We can note that AB=BAA \cap B = B \cap A
That is, the commutative property holds for the intersection of two sets.
Hence, we can able to say that the union of the sets and the intersection of the sets is commutative.
Now, we shall get into the solution.
It is given that MN=NRM \cup N = N \cup R
Union is operated on the sets M and N (i.e. MNM \cup N )
The union of sets M and N is commutative
Thus, MN=NMM \cup N = N \cup M
Since we have MN=NRM \cup N = N \cup Rand we found MN=NMM \cup N = N \cup M, we can able to conclude that M=RM = R
Similarly, the intersection is operated on the sets M and N (i.e.MNM \cap N )
The intersection of the sets M and N is commutative.
Thus, MN=NMM \cap N = N \cap M
Since we have MN=NRM \cap N = N \cap Rand we found MN=NMM \cap N = N \cap M, we can able to conclude that M=RM = R
Therefore, M=RM = Rand option C is the correct answer.

So, the correct answer is “Option C”.

Note: Note that the values of A union B and B union A are the same, also for an intersection B and B intersection A is the same. But for ABA - B(A difference B) and BAB - A(B difference A) are not the same. When the result is not changed though we change the order is said to be commutative.