Question

If LPG cylinder contains mixture of butane and isobutane,then the amount of oxygen that would be required for combustion of 1 kg of it will be

• A. 1.8 kg
• B. 2.7 kg
• C. 4.5 kg
• D. 3.58 kg

Answer 1

Answer: (D)

3.58 kg

Answer 2

Equation of combustion is $C_{4}H_{10}+13/2O_{2} \to 4CO_{2}+5H_{2}O$ Now $58\, kg$ $C_{4}H_{10}$ require $O_{2}$ $=13/2 \times 32\,kg=208\,kg$