Question

If log_0.3 (x–1) < log_0.09(x–1), then x lies in the interval-

• A. (2, )
• B. (1, 2)
• C. (–2, –1)
• D. None of these

Answer 1

Answer: (A)

(2, )

Answer 2

log₃ (x –1) < log.₃ $\sqrt{x - 1}$

Ž x – 1 > $\sqrt{x - 1}$

Ž x² – 3x + 2 > 0

Ž x < 1 and x > 2

But x can’t be less than 1, as negative of logarithm is not defined.

So, x Ī (2, )

Ž Choice [A] is correct.