Question

If $log2$ = 0.30103, find number of digits in 256

• A. 13
• B. 15
• C. 17
• D. 19

Answer 1

Answer: (C)

17

Answer 2

The correct is option (C): given $log2$=0.30103
let x= 256
$logx$=$log2^{56}$
$log(x)$=$56log(2)$
$log(x)$= $56 \times 0.30103$ = 16.85
The no. of digits in 256 = 17