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Question

Question: If \[\log x = 0\], then the value of \[x = ?\]...

If logx=0\log x = 0, then the value of x=?x = ?

Explanation

Solution

In this question, first of all identify the base of the given logarithm and use the formula to convert the given logarithm in terms of base and power to get the required solution.

Complete step-by-step answer :
Given that logx=0\log x = 0
We know that a natural logarithm has a base value of e=2.718e = 2.718.
So, we have logex=0{\log _e}x = 0
We know that, if logab=c{\log _a}b = c then ac=b{a^c} = b.
By using this statement, we have

logex=0 e0=x 1=x [e0=1] x=1  \Rightarrow {\log _e}x = 0 \\\ \Rightarrow {e^0} = x \\\ \Rightarrow 1 = x{\text{ }}\left[ {\because {e^0} = 1} \right] \\\ \therefore x = 1 \\\

Thus, the value of xx is 1 i.e., x=1x = 1.

Note : A natural logarithm has a base value of e=2.718e = 2.718. Always remember that anything power zero is equal to one. If logab=c{\log _a}b = c then ac=b{a^c} = b and vice versa.