If (log\_4m+log\_4n=log\_2(m+n)) where m and n are positive... | Quantitative Ability and Data Interpretation | SolveeIt | Solveeit

Today, August 24

Question

If $log_4m+log_4n=log_2(m+n)$ where m and n are positive real numbers, then which of the following must be true?

A

$\frac{1}{m} +\frac{1}{n} =1$

B

$m=n$

C

$m^2+n^2=1$

D

$\frac{1}{m} +\frac{1}{n} =2$

E

No values of m and n can satisfy the given equation

Answer

No values of m and n can satisfy the given equation

Explanation

Solution

The correct answer is option (E):No values of m and n can satisfy the given equation