Question

If lines $\frac{x-1}{-3}=\frac{y-2}{2k}=\frac{z-3}{2}$ and $\frac{x-1}{3k}=\frac{y-5}{1}=\frac{z-6}{-5}$ are mutually perpendicular then k is equal to

• A. $-\frac{10}{7}$
• B. $-\frac{7}{10}$
• C. -10
• D. -7

Answer 1

Answer: (A)

$-\frac{10}{7}$

Answer 2

The correct answer is Option (A) : $-\frac{10}{7}$