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Question: If length of common chord of two circles x<sup>2</sup> + y<sup>2</sup> + 8x + 1 = 0 and x<sup>2</sup...

If length of common chord of two circles x2 + y2 + 8x + 1 = 0 and x2 + y2 + 2my –1 = 0 is 262\sqrt{6}, then value of m are

A

±2

B

±3

C

±4

D

None of these

Answer

±3

Explanation

Solution

Common chord is S1 – S2 = 0

4x – my + 1 = 0

\ AC =15\sqrt{15}

AM = AB2\frac{AB}{2}= 6\sqrt{6}

\ CM = 3

\ 16+116+μ2\frac{| - 16 + 1|}{\sqrt{16 + \mu^{2}}}= 3

Ž m = ±3