Question
Question: If \(\left| {z - \dfrac{4}{z}} \right| = 2\), then the maximum value of \(\left| z \right|\) is equa...
If z−z4=2, then the maximum value of ∣z∣ is equal to
A. 3+1 B. 5+1 C. 2 D. 2 + 2
Solution
We have given z−z4=2 and we have to find maximum value of ∣z∣ so we have to start from given and use the concept of modulus and complex number so that we can make equation in form of ∣z∣ and then we will be able to find maximum value of ∣z∣.
Complete step by step answer:
We have given
z−z4=2
And we have to find ∣z∣
Now we can write ∣z∣= z−z4+z4
And we know the property of complex number
∣a+b∣⩽∣a∣+∣b∣
We will use this property in above equation as a=z−z4,b=z4
On applying this property we get,
∣z∣⩽z−z4+z4
As we have given in question z−z4=2 putting this value in above equation we get,
∣z∣⩽2+∣z∣4
On simplifying we get,
∣z∣−2−∣z∣4⩽0
∣z∣∣z∣2−2∣z∣−4⩽0
We can write it as also
∣z∣2−2∣z∣−4=0
Here this is quadratic equation in ∣z∣
And for the roots of quadratic equation we know the formula
If ax2+bx+c=0 is the form of quadratic equation then its roots are
x=2a−b±b2−4ac
Here applying same concept we get,
Hence roots of the quadratic equations are
z=±2+2−4+16 =1±5
And hence
0⩽∣z∣⩽1+5
And so max ∣z∣=1+5
Hence option B is the correct option.
Note:
Whenever we get this type of question the key concept of solving is we have to must remember properties of complex number and modulus like ∣a+b∣⩽∣a∣+∣b∣. These help in solving questions easily.