Question
Question: If \(\left( {x - 1} \right)\) is a factor of the polynomial \(3{x^3} - 2{x^2} + kx - 6\) , then find...
If (x−1) is a factor of the polynomial 3x3−2x2+kx−6 , then find the value of k ?
Solution
If (x−1) is a factor of the polynomial 3x3−2x2+kx−6, then x=1 is one of its zeroes. it satisfies the polynomial 3x3−2x2+kx−6. It means if we put x=1 in the polynomial 3x3−2x2+kx−6 then its value becomes equal to zero.
Complete step-by-step answer:
Here, the given polynomial is 3x3−2x2+kx−6 and its one of the factors is (x−1).
Since (x−1) is a factor of the given polynomial x=1 satisfy the given polynomial 3x3−2x2+kx−6.
Now, put x=1in the polynomial 3x3−2x2+kx−6 and then equate the result with zero.
Putting x=1in the polynomial 3x3−2x2+kx−6. We get,
⇒3(1)3−2(1)2+k(1)−6=0 ⇒3−2+k−6=0 ⇒k−5=0 ∴k=5
Thus, the required value of k is 5.
Note:
If a, b and c are the zeroes of any cubic polynomial f(x), then (x−a) , (x−b) and (x−c) are the factors of the given polynomial f(x).
The given polynomial 3x3−2x2+kx−6 is a cubic polynomial and its one of the zeroes is given to us then with this data we can find the value of k to get the required polynomial. Since this is a cubic it has three zero but only one zero is known so, its other two zeroes can be calculated as:
One of the factors of the given polynomial 3x3−2x2+kx−6 is given that is (x−1). Now, divide the given polynomial 3x3−2x2+kx−6 by (x−1) and it will give a quadratic polynomial then we have to calculate the zeros of a quadratic equation which can be calculated by using a well-known formula that is x=2a−b±b2−4ac where a is the coefficient of x2, b is the coefficient of x and c is the constant term of the quadratic polynomial ax2+bx+c.