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Question

Mathematics Question on Trigonometry

If [32+(12)i32(12)i]120=p+iq\left[\frac{\frac{\sqrt 3}{2}+(\frac{1}{2})i}{\frac{\sqrt 3}{2}-(\frac{1}{2})i}\right]^{120}=p+iq, then

A

p=cos20°, q=sin20°

B

p=-cos20°, q=-sin20°

C

p=cos20°, q=-sin20°

D

p=1, q=0

Answer

p=1, q=0

Explanation

Solution

The correct option is (D): p=1, q=0