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Question

Mathematics Question on Complex Numbers and Quadratic Equations

If (1+i1i)x=1,\left(\frac{1+i}{1-i}\right)^{x}=1, then

A

x=4nx = 4n, where nn is any positive integer

B

x=2nx = 2n, where nn is any positive integer

C

x=4n+1x = 4n+1, where nn is any positive integer

D

x=2n+1x = 2n+1, where nn is any positive integer

Answer

x=4nx = 4n, where nn is any positive integer

Explanation

Solution

1+i1i=(1+i)22=i\frac{1+i}{1-i}=\frac{\left(1+i\right)^{2}}{2}=i (1+i1i)x=ix\left(\frac{1+i}{1-i}\right)^{x}=i^{x} x=4n.\Rightarrow x = 4n. Hence, (A) is the correct answer.