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Question: If \(\left| \begin{matrix} x^{n} & x^{n + 2} & x^{n + 3} \\ y^{n} & y^{n + 2} & y^{n + 3} \\ z^{n} &...

If xnxn+2xn+3ynyn+2yn+3znzn+2zn+3\left| \begin{matrix} x^{n} & x^{n + 2} & x^{n + 3} \\ y^{n} & y^{n + 2} & y^{n + 3} \\ z^{n} & z^{n + 2} & z^{n + 3} \end{matrix} \right| = (x – y)(y – z)(z–x) (1x+1y+1z)\left( \frac{1}{x} + \frac{1}{y} + \frac{1}{z} \right)

then value of n is –

A

– 1

B

– 2

C

1

D

2

Answer

– 1

Explanation

Solution

Degree of L.H.S = n + (n + 2) + (n + 3) = 3 n + 5 ……. (1)

Degree of R.H.S = 1 + 1 + 1 + (–1) = 2 ……. (2)

from (1) & (2)

3 n + 5 = 2 Ž n = – 1