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Question: If \(\left| \begin{matrix} a^{n} & a^{n + 1} & a^{n + 2} \\ b^{n} & b^{n + 1} & b^{n + 2} \\ c^{n} &...

If anan+1an+2bnbn+1bn+2cncn+1cn+2\left| \begin{matrix} a^{n} & a^{n + 1} & a^{n + 2} \\ b^{n} & b^{n + 1} & b^{n + 2} \\ c^{n} & c^{n + 1} & c^{n + 2} \end{matrix} \right| = (a – b) (b – c) (c – a), then n is equal to

A

n =1

B

n = 2

C

Any value of n

D

None of these

Answer

None of these

Explanation

Solution

anbncn 1aa21bb21cc2\left| \begin{matrix} 1 & a & a^{2} \\ 1 & b & b^{2} \\ 1 & c & c^{2} \end{matrix} \right|

anbncn (a – b) (b – c) (c – a)

Ž comparing with R.H.S

n = 0