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Question: If \(\left| \begin{matrix} 1 & k & 3 \\ 3 & k & - 2 \\ 2 & 3 & - 1 \end{matrix} \right| = 0\), k is....

If ∣1k33k−223−1∣=0\left| \begin{matrix} 1 & k & 3 \\ 3 & k & - 2 \\ 2 & 3 & - 1 \end{matrix} \right| = 0, k is.

A

– 1

B

0

C

1

D

None of these

Answer

None of these

Explanation

Solution

∣1k33k−223−1∣=0⇒k=338\left| \begin{matrix} 1 & k & 3 \\ 3 & k & - 2 \\ 2 & 3 & - 1 \end{matrix} \right| = 0 \Rightarrow k = \frac{33}{8}.