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Question: If \[\left( {1{\text{ }},2} \right),\left( {4,y} \right),\left( {x,6} \right)\] and \[(3,5)\] are th...

If (1 ,2),(4,y),(x,6)\left( {1{\text{ }},2} \right),\left( {4,y} \right),\left( {x,6} \right) and (3,5)(3,5) are the vertices of a parallelogram taken in order , find x and y

Explanation

Solution

Hint : Use the property that diagonals of a parallelogram bisect each other. Then use the concept of midpoint in the coordinates of the centre of both the diagonals and equate the coordinates for the required values.

Complete step-by-step answer :
Lets say A,B,C,D are the vertices of a parallelogram ABCD and O is the midpoint where diagonals AC and BD intersect each other.
A(1,2)  B(4,y)  C(x,6)  D(3,5)A\left( {1,2} \right)\;B\left( {4,y} \right)\;C\left( {x,6} \right)\;D\left( {3,5} \right)

Now we have to find the coordinates of midpoint i.e. O
x- coordinate of O = x1+x22\dfrac{{{x_1} + {x_2}}}{2}
y- coordinate of O = y1+y22\dfrac{{{y_1} + {y_2}}}{2}
where x1x_1 = 1 and x2x_2 =x
y1y_1 =2 and y2y_2 =6
we will put values to find the coordinates of point O
x – coordinate of O = y=3y = 3 1+x2\dfrac{{1 + x}}{2}
y – coordinate of O = 2+62\dfrac{{2 + 6}}{2} = 82\dfrac{8}{2} = 4
coordinates of point O =( 1+X2\dfrac{{1 + X}}{2} , 4 ) ... ....(1)
We will repeat the same process but now we will consider diagonal BD and find the O coordinated by taking B and D coordinates into consideration.
x- coordinate of O = x1+x22\dfrac{{{x_1} + {x_2}}}{2}
y- coordinate of O = y1+y22\dfrac{{{y_1} + {y_2}}}{2}
where x1x_1 = 4 and x2x_2 =3
y1y_1 =y and y2y_2 =5
we will put values to find the coordinates of point O
x – coordinate of O = 4+32\dfrac{{4 + 3}}{2} = 72\dfrac{7}{2}
y – coordinate of O = y+52\dfrac{{y + 5}}{2}
coordinates of point O = (72,y+52)(\dfrac{7}{2},\dfrac{{y + 5}}{2}) .....(2)
now we will compare equation 1 and 2
(1+x2,4)(\dfrac{{1 + x}}{2},4) = (72,y+52)(\dfrac{7}{2},\dfrac{{y + 5}}{2})
We will compare x and y coordinates and find the value of x and y
1+x2=72\Rightarrow \dfrac{{1 + x}}{2} = \dfrac{7}{2}
1+x=7\Rightarrow 1 + x = 7
x=71\Rightarrow x = 7 - 1
x=6\Rightarrow x = 6
Similarly we will find the value of y
4=y+52\Rightarrow 4 = \dfrac{{y + 5}}{2}
8=y+5\Rightarrow 8 = y + 5
y=85\Rightarrow y = 8 - 5
y=3\Rightarrow y = 3
Therefore the x=6x=6 and y=3y=3 is the required answer.

Note : Revise the property of parallelogram that both the diagonals of parallelogram bisect each other. Revise the concept of midpoint of a line with the help of coordinates of endpoints of the line. Also mark the vertices ethier in clockwise direction or counterclockwise directions