Question

If law of conservation of mass was to hold true, then 20.8 g of $BaCl_2$ on reaction with 9 8 g of $H_2S0_4$ will produce 7.3 g of HCl and $BaS0_4$ equal to

• A. 11.65 g
• B. 23.3 g
• C. 25.5 g
• D. 30.6 g

Answer 1

Answer: (B)

23.3 g

Answer 2

$\underset{\text{208g}}{ {BaCl_{2}}} + \underset{\text{98g}}{ {H_{2}SO_{4}}} \to\underset{\text{233g}}{ {BaSO_{2}}}+ \underset{\text{73 g}}{ {2 Hcl}}$ Mass of $BaSO_{4}$ produced $=20.8+9.8 -7.3$ $=23.3\,g$