Question
Question: If l, m, n are the direction cosines of vector if \[l=\dfrac{1}{2}\], then the maximum value of lmn ...
If l, m, n are the direction cosines of vector if l=21, then the maximum value of lmn is
(a)41
(b)83
(c)21
(d)163
Solution
Hint: The direction cosine are given by the relation l2+m2+n2=1, put value of l in it. For terms m and n the arithmetic mean & geometric mean are of relation A.M ≥ G.M, thus get max value for mn according to the relation and find max value of lmn.
Complete step-by-step answer:
It is said that l, m and n are the direction cosines of a vector.
We have been given that, l=21.
We need to find the maximum value of lmn.
The direction cosines of a line parallel to any coordinate axis are equal to the direction cosine of the corresponding axis.
The direction cosines are associated by the relation,
⇒l2+m2+n2=1
Now let us put l=21 in the above expression. Thus we get,
⇒(21)2+m2+n2=1