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Question: If \(L\) denotes the inductance of an inductor through which a current \(i\) is flowing, the dimensi...

If LL denotes the inductance of an inductor through which a current ii is flowing, the dimensions of Li2Li^{2} are

A

ML2T−2ML^{2}T^{- 2}

B

Not expressible in MLTMLT

C

MLT−2MLT^{- 2}

D

M2L2T−2M^{2}L^{2}T^{- 2}

Answer

ML2T−2ML^{2}T^{- 2}

Explanation

Solution

12Li2\frac{1}{2}Li^{2} = Stored energy in an inductor

= [ML2T−2]\lbrack ML^{2}T^{- 2}\rbrack