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Question: If K<sub>1</sub> and K<sub>­2</sub> are the maximum kinetic energies of photo electrons emitted when...

If K1 and K­2 are the maximum kinetic energies of photo electrons emitted when lights of wavelength λ1 and λ2 respectively incident on a metallic surface and λ1 = 3λ2 . Then

A

K1>

B

K1<

C

K1 = 3K2

D

K2 = 3K1

Answer

K1<

Explanation

Solution

K1 = hcλ1\frac { \mathrm { hc } } { \lambda _ { 1 } } – φ

K2 = – φ

= (3hcλ1ϕ)(hcλ1ϕ)\frac { \left( \frac { 3 h c } { \lambda _ { 1 } } - \phi \right) } { \left( \frac { \mathrm { hc } } { \lambda _ { 1 } } - \phi \right) } = 3(hcλ1ϕ3)(hcλ1ϕ)\frac { 3 \left( \frac { \mathrm { hc } } { \lambda _ { 1 } } - \frac { \phi } { 3 } \right) } { \left( \frac { \mathrm { hc } } { \lambda _ { 1 } } - \phi \right) }

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