Question
Chemistry Question on Solutions
If Ksp of Ag2CO3 is 8×10−12, the molar solubility of Ag2CO3 in 0.1MAgNO3 is:
A
(A) 8 × 10-12 M
B
(B) 8 × 10-10 M
C
(C) 8 × 10-11 M
D
(D) 8 × 10-13 M
Answer
(B) 8 × 10-10 M
Explanation
Solution
Explanation:
Ag2CO3( s)⇌2Ag+(aq.)+CO3−2(aq)Ksp=[Ag+]2[CO3−2]8×10−12=(0.1+2S)2(S)As Ksp is so small, so 0.1+2S=0.1S=8×10−10MHence, the correct option is (B).