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Question

Chemistry Question on Solutions

If Ksp of Ag2CO3 is 8×10−12, the molar solubility of Ag2CO3 in 0.1MAgNO3 is:

A

(A) 8 × 10-12 M

B

(B) 8 × 10-10 M

C

(C) 8 × 10-11 M

D

(D) 8 × 10-13 M

Answer

(B) 8 × 10-10 M

Explanation

Solution

Explanation:
Ag2CO3( s)⇌2Ag+(aq.)+CO3−2(aq)Ksp=[Ag+]2[CO3−2]8×10−12=(0.1+2S)2(S)As Ksp is so small, so 0.1+2S=0.1S=8×10−10MHence, the correct option is (B).