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Question: If kinetic energy of a proton is increased nine times the wavelength of the de-Broglie wave associat...

If kinetic energy of a proton is increased nine times the wavelength of the de-Broglie wave associated with it would become

A

3 times

B

9 times

C

13\frac{1}{3} times

D

19\frac{1}{9} times.

Answer

13\frac{1}{3} times

Explanation

Solution

l = h2mE\frac{h}{\sqrt{2mE}}

λ1λ2\frac{\lambda_{1}}{\lambda_{2}} = E2E1\sqrt{\frac{E_{2}}{E_{1}}} = 9E1E1\sqrt{\frac{9E_{1}}{E_{1}}} = 3

l2 = 13\frac{1}{3}l1.