Question

If kinetic energy of a body is increased by 300% than percentage change in momentum will be

• A. 100%
• B. 150%
• C. 265%
• D. 73.20%

Answer 1

Answer: (A)

100%

Answer 2

The correct option is (A) : 100%

P1 = $\sqrt{2}$mE1 ; P2 = $\sqrt{2}$mE2

=$\sqrt{2}$m($\frac{E_1+300}{100E_1}$) =√2m(4E1)=2P1

∴ % change = $\frac{P_2-P_1}{P_1}\times100$ = $\frac{2P_2-P_1}{P_1}\times100$=100%