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Question: If \({K_i}\) and \({K_p}\) are the effective spring constant in series and parallel combination of s...

If Ki{K_i} and Kp{K_p} are the effective spring constant in series and parallel combination of springs as shown in figure, find KiKp\dfrac{{{K_i}}}{{{K_p}}}.

A. 9/2
B. 3/7
C. 2/9
D. 7/3

Explanation

Solution

Try to recall the concept of dividing current in branches having resistance R1{R_1} and R2{R_2} which are firstly connected in series and secondly in parallel. From that concept we will get the idea of adding spring constants, either springs are connected in series or connected in parallel. And then simply take the ratio of and we will get the answer.

Complete step by step answer:
First we will see the concept of adding spring constants when they are connected in
1. Series
2. Parallel

Case:1 When Springs are connected in series.
When two spring are connected in series having spring constants K1{K_1} and K2{K_2} as shown in below figure

Then the resulting Spring constant Kr{K_r} is given by the formula:
1K=1K1+1K2\dfrac{1}{{{K_{}}}} = \dfrac{1}{{{K_1}}} + \dfrac{1}{{{K_2}}}
Now from the question
K1=K{K_1} = K
K2=2K{K_2} = 2K
Putting values in formula
1Kr=1K+12K\dfrac{1}{{{K_r}}} = \dfrac{1}{K} + \dfrac{1}{{2K}}
1Kr=2K+K2K2\dfrac{1}{{{K_r}}} = \dfrac{{2K + K}}{{2{K^2}}}
1Kr=32K\dfrac{1}{{{K_r}}} = \dfrac{3}{{2K}}
Kr=2K3{K_r} = \dfrac{{2K}}{3}

Case 2: When springs are connected in parallel
When two spring are connected in parallel having spring constants K1{K_1} and K2{K_2} as shown in below figure

Then the resulting Spring constant Kp{K_p} is given by the formula:
Kp=K1+K2{K_p} = {K_1} + {K_2}
Given values of K1{K_1} and K2{K_2}from question:
K1=K{K_1} = K
K2=2K{K_2} = 2K
Putting values in above equation:
Kp=K+2K{K_p} = K + 2K
Kp=3K{K_p} = 3K
Now we have both spring constant
KiKp=KrKp=2K33K\dfrac{{{K_i}}}{{{K_p}}} = \dfrac{{{K_r}}}{{{K_p}}} = \dfrac{{\dfrac{{2K}}{3}}}{{3K}}
KiKp=29\dfrac{{{K_i}}}{{{K_p}}} = \dfrac{2}{9}
Hence, option C is correct.

Note: This concept can be used to combine two springs and replace it with a new one. Not only we are bound to combine two springs we can also combine many strings. If the spring constant of a spring is high then it is difficult to stretch it more while spring having less or low spring constant can be elongated much more than the previous one.