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Question: If it is given that \(\left( x-4 \right)\) is a geometric mean of \(\left( x-5 \right)\) and \(\left...

If it is given that (x4)\left( x-4 \right) is a geometric mean of (x5)\left( x-5 \right) and (x2)\left( x-2 \right), then find the value of xx.

Explanation

Solution

In this problem we need to calculate the value of xx where the geometric mean of (x5)\left( x-5 \right) and (x2)\left( x-2 \right) is (x4)\left( x-4 \right). We know that the geometric mean of the numbers aa and bb is ab\sqrt{ab}. So, we will first calculate the geometric mean of (x5)\left( x-5 \right) and (x2)\left( x-2 \right) by using the above formula. After that we will equate the calculated value of the geometric mean to the given geometric mean which is (x4)\left( x-4 \right) and simplify the equation to get the required result.

Complete step by step answer:
Given that, the geometric mean of (x5)\left( x-5 \right) and (x2)\left( x-2 \right) is (x4)\left( x-4 \right).
We know that the geometric mean of the numbers aa and bb is ab\sqrt{ab}. From this formula the geometric mean of the numbers (x5)\left( x-5 \right) and (x2)\left( x-2 \right) is given by
m=(x5)(x2)m=\sqrt{\left( x-5 \right)\left( x-2 \right)}
But in the problem, we have the geometric mean of the numbers as (x5)\left( x-5 \right). So, equating the both the values, then we will get
(x4)=(x5)(x2)\left( x-4 \right)=\sqrt{\left( x-5 \right)\left( x-2 \right)}
Squaring on both sides of the above equation, then we will have
(x4)2=(x5)(x2){{\left( x-4 \right)}^{2}}=\left( x-5 \right)\left( x-2 \right)
Using the formulas (ab)2=a22ab+b2{{\left( a-b \right)}^{2}}={{a}^{2}}-2ab+{{b}^{2}}, (xa)(xb)=x2(a+b)x+ab\left( x-a \right)\left( x-b \right)={{x}^{2}}-\left( a+b \right)x+abin the above equation, then we will get
x22(x)(4)+42=x2(5+2)x+(5)(2){{x}^{2}}-2\left( x \right)\left( 4 \right)+{{4}^{2}}={{x}^{2}}-\left( 5+2 \right)x+\left( 5 \right)\left( 2 \right)
Simplifying the above equation by cancelling the common term x2{{x}^{2}} which is on both sides of the equation, then we will get
8x+16=7x+10-8x+16=-7x+10
Rearrange the terms in the above equation, so that all the variables at one side and constants at one side, then we will get
8x7x=1610 x=6 \begin{aligned} & 8x-7x=16-10 \\\ & \therefore x=6 \\\ \end{aligned}

Note: In this problem we don’t have calculated the geometric mean by simplifying the equation m=(x5)(x2)m=\sqrt{\left( x-5 \right)\left( x-2 \right)} which takes too much of time and gives some complexity in further steps. So, use simple mathematical operations and solve the problem in an easiest way.