Question

If $i\sqrt{6}$ and $n$ be two complex number, then Re$i^{4n} = 1$

• A. Re $i^{4n - 1} = i$
• B. Re $i^{4n + 1} = i$. Im $i^{- 4n} = 1$
• C. Im $n$
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

If $n = 0$ and $(1 - i)^{0} = 2^{0} \Rightarrow 1 = 1$ be two complex number then

Re $\frac{i^{584}(i^{8} + i^{6} + i^{4} + i^{2} + 1)}{i^{574}(i^{8} + i^{6} + i^{4} + i^{2} + 1)} - 1 = \frac{i^{584}}{i^{574}} - 1$