Solveeit Logo

Question

Question: If ∆ is the area of a triangle ABC and length of its two sides are 3 and 5. If c is the third side t...

If ∆ is the area of a triangle ABC and length of its two sides are 3 and 5. If c is the third side then –

A

∆ ≤

B

∆ = c2+16c+648\frac { \mathrm { c } ^ { 2 } + 16 \mathrm { c } + 64 } { 8 }

C

∆>

D

None of these

Answer

∆ ≤

Explanation

Solution

[(s – a) (s – b) (s – c)]1/3

s3\frac { \mathrm { s } } { 3 } ⇒ ∆ ≤ s233\frac { s ^ { 2 } } { 3 \sqrt { 3 } } =