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Question: If \(*\) is defined by a\(*\) b \( = \) \(a - {b^2}\) and \( \oplus \) is defined by \(a \oplus b = ...

If * is defined by a* b == ab2a - {b^2} and \oplus is defined by ab=a2+ba \oplus b = {a^2} + b, where aa and bb are integers, then (34)\left( {3 \oplus 4} \right)* 55 is equal to
A.164A.164
B.38B.38
C.12C.12
D.28D.28
E.144E.144

Explanation

Solution

Hint – In this question, we have to apply the values of the given operations ' \oplus ' and '*', and then by considering the numbers as a'a' and b'b'. It is a relation or expression involving one or more variables.
Complete step-by-step answer:
It is given that, symbol * is defined by ab=ab2a*b = a - {b^2} and the symbol '\oplus' is defined by aba \oplus b =a2+b = {a^2}+b , where a'a' and b'b' are integers.
We have to find the value of (35)\left( {3 \oplus 5} \right) 5*5
Firstly, we will calculate 343 \oplus 4
Let us consider, a=3a = 3 and b=4b = 4
Since, ab=a2+ba \oplus b = {a^2} + b
34=32+4 34=9+4 34=13  \Rightarrow 3 \oplus 4 = {3^2} + 4 \\\ \Rightarrow 3 \oplus 4 = 9 + 4 \\\ \Rightarrow 3 \oplus 4 = 13 \\\
Now, we will find (34)5\left( {3 \oplus 4} \right)*5
Again, consider as a=34a = 3 \oplus 4 that is 13 and b=5b = 5
ab=ab2 135=1352 135=1325 135=12  a*b = a - {b^2} \\\ \Rightarrow 13*5 = 13 - {5^2} \\\ \Rightarrow 13*5 = 13 - 25 \\\ \Rightarrow 13*5 = - 12 \\\
Therefore, the required values of (34)5\left( {3 \oplus 4} \right)*5 is -12
Note – In this type of question, one must know that the approach we have used in this particular question is binary operations that is defined as an operation which is performed on a set AA. The function is given by : AA \to A. So the operation * performed on operands a and b is denoted by
a*b.